int __fastcall Java_jp_colopl_util_Crypto_getKeySpec(int a1)
{
int v1; // r5@1
int v2; // r2@1
int v3; // r7@2
int v4; // r0@3
int v5; // r0@4
int v6; // r6@4
int v7; // r0@4
v1 = a1;
v2 = (*(int (**)(void))(*(_DWORD *)a1 + 668))();
if ( v2 )
{
v2 = (*(int (__fastcall **)(int, signed int))(*(_DWORD *)v1 + 704))(v1, 32);
v3 = v2;
if ( v2 )
{
v4 = (*(int (__fastcall **)(int, int, _DWORD))(*(_DWORD *)v1 + 736))(v1, v2, 0);
v2 = v4;
if ( v4 )
{
*(_BYTE *)v4 = 48;
*(_BYTE *)(v4 + 1) = 108;
*(_BYTE *)(v4 + 2) = 113;
*(_BYTE *)(v4 + 3) = 71;
*(_BYTE *)(v4 + 6) = 102;
*(_BYTE *)(v4 + 4) = 84;
*(_BYTE *)(v4 + 8) = 75;
*(_BYTE *)(v4 + 5) = 121;
*(_BYTE *)(v4 + 7) = 121;
*(_BYTE *)(v4 + 9) = 57;
*(_BYTE *)(v4 + 23) = 121;
*(_BYTE *)(v4 + 10) = 73;
*(_BYTE *)(v4 + 24) = 119;
*(_BYTE *)(v4 + 11) = 50;
*(_BYTE *)(v4 + 25) = 72;
*(_BYTE *)(v4 + 12) = 107;
*(_BYTE *)(v4 + 26) = 76;
*(_BYTE *)(v4 + 13) = 118;
*(_BYTE *)(v4 + 14) = 53;
*(_BYTE *)(v4 + 17) = 87;
*(_BYTE *)(v4 + 21) = 118;
*(_BYTE *)(v4 + 27) = 98;
*(_BYTE *)(v4 + 29) = 98;
*(_BYTE *)(v4 + 15) = 46;
*(_BYTE *)(v4 + 18) = 110;
*(_BYTE *)(v4 + 22) = 99;
*(_BYTE *)(v4 + 30) = 122;
*(_BYTE *)(v4 + 16) = 89;
*(_BYTE *)(v4 + 20) = 89;
*(_BYTE *)(v4 + 31) = 74;
*(_BYTE *)(v4 + 19) = 83;
*(_BYTE *)(v4 + 28) = 90;
(*(void (__fastcall **)(int, int))(*(_DWORD *)v1 + 768))(v1, v3);
v5 = (*(int (__fastcall **)(int, _DWORD))(*(_DWORD *)v1 + 24))(v1, "javax/crypto/spec/SecretKeySpec");
v6 = v5;
v7 = (*(int (__fastcall **)(int, int, _DWORD, _DWORD))(*(_DWORD *)v1 + 132))(
v1,
v5,
"<init>",
"([BLjava/lang/String;)V");
v2 = (*(int (__fastcall **)(int, int, int, int))(*(_DWORD *)v1 + 112))(v1, v6, v7, v3);
}
}
}
return v2;
}
from: 賣萌黑貓的猜謎/黑貓維茲/クイズRPG 魔法使いと黒貓のウィズ(jp.colopl.quizwiz) 的逆向工程 ; 論野生技術&二次元
那圖好像死神的那個。前天psp裡面看到了
是吧
這不是niconiconi嘛
不是直接 md5sum /path/of/file 就好了嗎?
卧槽還能這樣
在 v1 那裡按 = 選擇 a1在 a1 那裡按 Y 輸入 JNIEnv *
哈哈哈哈沒事,看得懂就好
難道你看的懂 *(_DWORD *)a1 + 668 是調用的哪個函數?
膜拜